9(x+3)²-16(x+2)²=0怎么解?
问题描述：
9(x+3)²-16(x+2)²=0怎么解?
答
9(x+3)²-16(x+2)²=0
[3(x+3)+4(x+2）][3(x+3)-4(x+2)]=0
(7x+17)(-x+1)=0
x1=-17/7,x2=1