如何计算1/(3*7)+1/(7*11)+1/(11*15)+.+1/(39*43)=
问题描述:
如何计算1/(3*7)+1/(7*11)+1/(11*15)+.+1/(39*43)=
答
原式=1/4*[(1/3)-(1/7)+(1/7)-(1/11)+.+(1/39)-(1/43)]=1/4*[(1/3)-(1/43)]=10/129
如何计算1/(3*7)+1/(7*11)+1/(11*15)+.+1/(39*43)=
原式=1/4*[(1/3)-(1/7)+(1/7)-(1/11)+.+(1/39)-(1/43)]=1/4*[(1/3)-(1/43)]=10/129