(x+y)^2(x-y)+(x+y)(y-x)^2 提取公因式
问题描述:
(x+y)^2(x-y)+(x+y)(y-x)^2 提取公因式
答
(x+y)^2(x-y)+(x+y)(y-x)^2
=(x+y)^2(x-y)+(x+y)(x-y)^2
=(x+y(x-y)[(x+y)+(x-y)]
=(x+y(x-y)(x+y+x-y)
=2x(x+y)(x-y)