1.已知正方形ABCD的边BC的延长线上取一点E,使CD=CE,连结AE交CD于F,角ADE=( )度.
问题描述:
1.已知正方形ABCD的边BC的延长线上取一点E,使CD=CE,连结AE交CD于F,角ADE=( )度.
2.在菱形ABCD中,E、F分别在BC和CD上,且三角形AEF是等边三角形,AE=AB,则角BAD=( )度
A.95 B.100 C.105 D.120
答
1.40
2.A