1-(x-1)/3=(x+3)/2 （2y+1）/4-1=y-（10y+1）/12 3x+（x+1）/2=3-（2x-1）/3
问题描述：
1-(x-1)/3=(x+3)/2 （2y+1）/4-1=y-（10y+1）/12 3x+（x+1）/2=3-（2x-1）/3
答
1-(x-1)/3=(x+3)/2 两边同时乘以6得6-2(x-1)=3(x+3)6-2x+2=3x+93x+2x=6+2-95x=-1x=-1/5（2y+1）/4-1=y-（10y+1）/12 两边同时乘以12得3(2y+1)-12=12y-(10y+1)6y+3-12=12y-10y-16y-12y+10y=-1-3+124y=8y=23x+（x+1）/...