1.2[x-3]^2=[2x-5][2x+1]
问题描述：
1.2[x-3]^2=[2x-5][2x+1]
2.2y^2+8y+8=0
3.-3/2x^2+x+2=0
答
1. 2[x-3]^2=[2x-5][2x+1] 2x^2-12x+18=4x^2+2x-10x-52x^2+4x-23=0x^2+2x=23/2[x+1]^2=25/2x+1=+/-5/根2x1=-1+5/根2x2=-1-5/根22. 2y^2+8y+8=0 y^2+4y+4=0[y+2]^2=0y=-23. -3/2x^2+x+2=0x^2-2/3x-4/3=0[x-1/3]^2=4/3...