f(2x+1/2x-2)-1/2f(x)=x,求f(x)
问题描述：
f(2x+1/2x-2)-1/2f(x)=x,求f(x)
求解
答
f[(2x+1)/(2x-2)] -(1/2) f(x) = x设 (2x+1)/(2x-2) = y,则2x + 1 = 2xy - 2y2x - 2xy = -2y - 1x(2 - 2y) = -2y -1x = (2y +1)/(2y -2)因此f(y) - (1/2) f[(2y+1)/(2y-2)] = (2y+1)/(2y-2)y 只是一个符号而已.重新...