把多项式(xy-1)^2+(x+y-2)(x+y-2)(x+y-2xy)分解因式,再求值(x=6,y=11)

问题描述:

把多项式(xy-1)^2+(x+y-2)(x+y-2)(x+y-2xy)分解因式,再求值(x=6,y=11)

(XY-1)2 +(x + y的-2)(x + y的-2XY) = X 2 Y 2-2XY +1 +(+ y)的2-2XY(+ y)的-2 (X + Y)+4 XY= X 2 Y 2 +2 +1 XY +(X + Y)2-2XY(X + Y)-2(X + Y) =(XY 1)2 -2板(xy +1)(X + Y)+(+ y)的2 ...