因式分解:(2a+1)(3a-5)-4(a-2)

问题描述:

因式分解:(2a+1)(3a-5)-4(a-2)

(2a+1)(3a-5)-4(a-2)
=6a²-10a+3a-5-4a+8
=6a²-11a+3
=(2a-3)(3a-1)
不懂还可问,o(∩_∩)o