函数y=sin(x+3/5π)+sin(x-3/5π)的周期为?
问题描述:
函数y=sin(x+3/5π)+sin(x-3/5π)的周期为?
答
y=sin(x+3/5π)+sin(x-3/5π)
=sinxcos3/5π+cosxsin3/5π+sinxcos3/5π-cosxsin3/5π
=2cos3/5π*sinx
所以T=2π/1=2π