(a-b-c)乘以(b+c-a)的2次方乘以(c-a+b)的3次方

问题描述:

(a-b-c)乘以(b+c-a)的2次方乘以(c-a+b)的3次方

原式=(a-b-c)*[-(a-b-c)]^2*[-(a-b-c)]^3
=(a-b-c)*(a-b-c)^2*[-(a-b-c)^3]
=-(a-b-c)^6