电阻r1和r2并联后总电阻为60欧,已知r1是80欧,求r2

问题描述:

电阻r1和r2并联后总电阻为60欧,已知r1是80欧,求r2

由并联电阻关系可得:
1/R=1/R1+1/R2
1/R2=1/R-1/R1=1/60-1/80=1/240
R2=240(Ω)
答:略.