当X²+2Y²-6X+2√2*Y+10=0,求4Y2/2X
问题描述：
当X²+2Y²-6X+2√2*Y+10=0,求4Y2/2X
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2√2*Y也就是2倍根号2乘以Y
答
把10拆成9和1,得X²+2Y²-6X+2√2*Y+9+1=0配方X²-6X+9+2Y²2√2*Y+1=0化简X²-6X+9=(x-3)^22Y²2√2*Y+1=（√2Y+1）^2 所以原式化简为(x-3)^2+（√2Y+1）^2=0所以(x-3)^2=0解得X=3所以（√...