{x/3-y=5 (1) {x/4-y=1 (2) {5x+2y=5 (1) {2x+5y=8 (2)
问题描述:
{x/3-y=5 (1) {x/4-y=1 (2) {5x+2y=5 (1) {2x+5y=8 (2)
解下列方程组
{x/3-y=5 (1)
{x/4-y=1 (2)
{5x+2y=5(1)
{2x+5y=8(2)
答
第一题x=48,y=11(两式相减,消去y解得x)
第二题x=3/7,y=10/7 ((1式乘以5)减去(2式乘以2)消去y解得x)