因式分解x^4+4x^2y^2+16y^4

问题描述:

因式分解x^4+4x^2y^2+16y^4

^是什么意思?

x⁴+4x²y²+16y⁴
=x⁴+8x²y²+16y⁴-4x²y²
=(x²+4y²)²-(2xy)²
=(x²+4y²+2xy)(x²+4y²-2xy)

如果不懂,请追问,祝学习愉快!

x^4+4x^2y^2+16y^4
=(x²+2y²)²

x^4+4x^2y^2+16y^4
=x^4+8x^2y^2+16y^4-4x²y²
=(x²+4y²)²-(2xy)²
=(x²+2xy+4y²)(x²-2xy+4y²)

原式=x^4+8x²y²+16y^4-4x²y²
=(x²+4y²)²-4x²y²
=(x²+2xy+4y²)(x²-2xy+4y²)