如图在三角形abc∠c=90°,ac=bc=ae,de⊥ab于e,三角形dbe的周长为6cm,则ab=

问题描述:

如图在三角形abc∠c=90°,ac=bc=ae,de⊥ab于e,三角形dbe的周长为6cm,则ab=

答:∠C = 90°,CA = CB,∴△CAB是等腰直角△,∴∠B = 45°,∴△DEB是等腰直角△∴DE = BE,∵AD的角平分线,∴DC = DE,∴AC = AE,∴△DEB周边= DE + BE + DB = DC + DB + BE = CB + BE = AE + EB = AB = 6厘米,∴△DE...谢谢你