因式分解：x的5次方-2x³y²+x*y的4次方摆脱,要好好答,
问题描述：
因式分解：x的5次方-2x³y²+x*y的4次方
摆脱,要好好答,
答
x^5-2x^3y^2+xy^4
=x（x^4-2x²y²+y^4）
=x（x²-y²）²
=x（x+y）²（x-y）²
答
x的5次方-2x³y²+x*y的4次方=X(X^4-2X^2*Y^2+Y^4)=X(X^2-y^2)^2=X(X+Y)^2(X-Y)^2
答
=x﹙x4-2x2y2+y4﹚
=x﹙x2-y2﹚2
=x﹙x-y﹚2﹙x+y﹚2
答
x的5次方-2x³y²+x*y的4次方
=x(x的4次方-2x²y²+y的4次方)
=x(x²-y²)²
=x[(x+y)(x-y)]²
=x(x+y)²(x-y)²
答
x^5-2x^3y^2+xy^4
=x(x^4-2x^2y^2+y^4)
=x(x^2-y^2)^2
=x(x+y)^2(x-y)^2