化简[（x的平方－4）／(x的平方－4X+4)+(2-X)/(X＋2)]÷x/(x-2) 的结果是?
问题描述：
化简[（x的平方－4）／(x的平方－4X+4)+(2-X)/(X＋2)]÷x/(x-2) 的结果是?
答
[ (x² - 4) / (x² -4x +4) + (2-x)/(x+2) ] ÷x/(x-2)
= [ (x+2)(x-2)/(x-2)(x-2) - (x-2)/(x+2) ]÷x/(x-2)
= [ (x+2)/(x-2) - (x-2)/(x+2) ]÷x/(x-2)
= [ (x² +4x +4 - x² +4x -4 ) / (x+2)(x-2) ]÷x/(x-2)
= 8x / (x+2)(x-2) × (x-2)/x
= 8/(x+2)
答
[（x的平方－4）／(x的平方－4X+4)+(2-X)/(X＋2)]÷x/(x-2)= [(x+2)(x-2)/(x-2)^2 -(x-2)/(x+2)] × (x-2)/x= [(x+2)/(x-2) -(x-2)/(x+2)] × (x-2)/x= [(x+2)^2 -(x-2)^2] / [(x+2)(x-2)] × (x-2)/x= 8x / [(x+2)(...