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根号下[x^2+(y+4)^2] + 根号下[x^2+(y-4)^2] = 12

分类: 作业答案 • 2021-12-20 07:46:54
问题描述：

根号下[x^2+(y+4)^2] + 根号下[x^2+(y-4)^2] = 12

答

根号下[x^2+(y+4)^2] + 根号下[x^2+(y-4)^2] = 12√[x^2+(y+4)^2] + √[x^2+(y-4)^2] = 12[x^2+(y+4)^2] + 2√[x^2+(y+4)^2][x^2+(y-4)^2] +[x^2+(y-4)^2] = 144x^2+y^2+8y+16 + 2√[x^2+(y+4)^2][x^...

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