等差数列{an},{bn}的前n项和分别为Sn,Tn,若Sn/Tn=2n/3n+1,则a6/b6

问题描述:

等差数列{an},{bn}的前n项和分别为Sn,Tn,若Sn/Tn=2n/3n+1,则a6/b6

S11/T11=2*11/(3*11+1)=22/34=11/17
a6/b6
=11a6/(11b6)
=S11/T11
=11/17
如果认为讲解不够清楚,