(x平方+2x+1)分之1的积分怎么求

问题描述:

(x平方+2x+1)分之1的积分怎么求

∫ 1/(x^2+2x+1) dx
=∫ 1/(x+1)^2 dx
= -∫ d(1/(x+1))
= - 1/(x+1) + C

=∫[d(x+1)]/(x+1)²
=∫(x+1)^(-2)d(x+1)
=(x+1)^(-2+1)/(-2+1)+C
=-1/(x+1)+C