解方程或不等式①（x-1）平方-（x-1）（x+5）=17.
问题描述：
解方程或不等式①（x-1）平方-（x-1）（x+5）=17.
答
(x-1）^2-（x-1）（x+5）=17
(x-1)(x-1)-(x-1)(x+5)=17
x^2-x-x+1-(x^2+5x-x-5)=17
x^2-x-x+1-x^2-5x+x+5-17=17-17
-6x-11=0
-6x-11-6x=6x
-11=6x
-11除以6=6x除以6
x=-6分之11
答
x^2-2x+1-(x^2+4x-5)-17=0
-6x-11=0
x=-11/6
答
(x-1)²-(x-1)(x-1+6)=17
(x-1)²-(x-1)²-6(x-1)=17
-6x+6=17
-6x=11
x=-11/6
答
(x-1)²-(x-1)(x+5)=17
(x²-2x+1)-(x²+4x-5)=17
x²-2x+1-x²-4x+5=17
-2x-4x=17-1-5
-6x=11
x=-11/6
答
①（x-1）²-（x-1）（x+5）=17
x²－2x＋1－﹙x²＋5x－x－5﹚＝17
x²－2x+1－x²－4x＋5=17
－2x－4x=17－1－5
－6x=11
x＝－11/6