化简(tan5π/4+tan5π/12)/(1-tan5π/12) 注意分母啊 细心!

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• 化简(tan5π/4+tan5π/12)/(1-tan5π/12)
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• 化简(tan5π/4+tan5π/12)/(1-tan5π/12) 注意分母啊 细心!
• 化简(tan5π/4+tan5π/12)/(1-tan5π/12)(tan 5π/4 + tan 5π/12)/(1-tan 5π/12) =(tan π/4 + tan π/6+π/4 )/(1-tan π/4*tan π/6+π/4 ) =tan(π/4 + π/6+π/4 )=tan(π/2+π/6) 请问我这样算错在哪呢?tan π/2不是无意义吗?
• 13、化简：（1）3√15sinx+3√5cosx （2）3/2cosx-√3/2sinx （3）√3sinx/2+cosx/2（4）√2/4sin(π/4-x)+√6/4cos(π/4-x) （5）sin347°cos148°+sin77°cos58°（6）sin164°sin224°+sin254°sin314° （7）sin(a+b)cos(γ-b)-cos(b+a)sin(b-γ)（8）sin(a-b)cos(b-γ)-cos(a-b)sin(γ-b)（9）tan5π/4+tan5π/12 / 1-tan5π/12 （10）sin(a+b)-2sinacosb) / 2sinasinb+cos(a+b)
• 化简(tan5π/4+tan5π/12)/(1-tan5π/12)
• 已知sin(π／4 +α）*sin（π／4 -α）＝1/6,α∈（π／2,π）,求sin4α
• 化简(tan5π/4+tan5π/12)/(1-tan5π/12)(tan 5π/4 + tan 5π/12)/(1-tan 5π/12) =(tan π/4 + tan π/6+π/4 )/(1-tan π/4*tan π/6+π/4 ) =tan(π/4 + π/6+π/4 )=tan(π/2+π/6) 请问我这样算错在哪呢?tan π/2不是无意义吗?