sin(-30)°+cos180°—cos9π/4—tan(-60)°
问题描述:
sin(-30)°+cos180°—cos9π/4—tan(-60)°
答
sin(-30)°+cos180°—cos9π/4—tan(-60)°
=-sin30°+cos180°—cosπ/4+tan60°
=-1/2+(-1)- √2/2+√3
=-3/2-√2/2+√3
答
sin(-30)°+cos180°—cos9π/4—tan(-60)°
=-1/2-1-√2/2+√3
=-3/2-√2/2+√3