用因式分解法解出下列方程：(4x-1)(5x+7)=03x(x-1)＝2(1-x)(x+1)^2-25=02(x-3)=x^2-9
问题描述：
用因式分解法解出下列方程：
(4x-1)(5x+7)=0
3x(x-1)＝2(1-x)
(x+1)^2-25=0
2(x-3)=x^2-9
答
4x-1=0 5x+7=0
x=1/4 x=-7/5
(3x+2)(x-1)=0
3x+2=0 x-1=0
x=-2/3 x=1
(x+1-5)(x+1+5)=0
x-4=0 x+6=0
x=4 x=-6
2(x-3)=(x-3)(x+3)
0=(x-3)(x+3-2)
x-3=0 x+1=0
x=3 x=-1
答
(4x-1)(5x+7)=0
x1=1/4，x2= -7/5
3x(x-1)＝2(1-x)
3x(x-1)+2(x-1)=0
(x-1)(3x+2)=0
x1=1,x2=-2/3
(x+1)^2-25=0
(x+1+5）（x+1-5）=0
x1=-6，x2=4
2(x-3)=x^2-9
2（x-3)-（x+3）（x-3）=0
（x-3）（2-x-3）=0
x1=3，x2= -1
答
(4x-1)(5x+7)=04x-1=0或5x+7=0x=1/4或x=-7/53x(x-1)=2(1-x)3x(x-1)-2(1-x)=03x(x-1)+2(x-1)=0(x-1)(3x+2)=0x=1或x=-2/3(x+1)²-25=0(x+1+5)(x+1-5)=0(x+6)(x-4)=0x=4或x=-62(x-3)=x²-92(x-3)-(x²-9)=0...