已知tan(a-π/3)=-√3/5,则tana=

问题描述:

已知tan(a-π/3)=-√3/5,则tana=

tan(a-π/3)=-√3/5,则
tana=tan[(a-π/3)+π/3]=(-√3/5+√3)/(1-(-√3/5)*√3)=√3/2