1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80=?要简便算法啊,
问题描述：
1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80=?要简便算法啊,
答
分组,列项
1/3=1/2*(1-1/3)
1/15=1/2*(1/3-1/15)
.
1/8=1/2*(1/2-1/4)
1/24=1/2*(1/4-1/6)
.
1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80
=(1/3+1/15+1/35+1/63)+(1/8+1/24+1/48+1/80)
=1/2*(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9)+1/2*(1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10)
=1/2*(1-1/9+1/2-1/10)
=1/2*58/45
=58/90