已知2sin^α+sin2α/1+tanα=k(π/4
问题描述：
已知2sin^α+sin2α/1+tanα=k(π/4
答
(2sin^2 α+2sinα*cosα)/(1+tanα)=k (2sin^2 α+2sinα*cosα)/(1+tanα)=2sinacosa(sina+cosa)/(sina+cosa)=2sinacosa=k (sinα-cosα)^2=1-2sinacosa=1-k sinα-cosα=±√（1-k）