由4x-3y-6z=0,x+2y-7z=0(xyz≠0),怎么解得 x=3z,y=2z,
问题描述:
由4x-3y-6z=0,x+2y-7z=0(xyz≠0),怎么解得 x=3z,y=2z,
答
4x-3y-6z=0,①
x+2y-7z=0 ②
①×2+②×3得:
8x-12z+3x-21z=0
11x-33z=0
11x=33z
∴x=3z
①-②×4得:
-3y-8y-6z+28z=0
-11y+22z=0
-11y=-22z
∴y=2z