因式分解:(x²+3x-2)(x²+3x+4)+9=?

问题描述:

因式分解:(x²+3x-2)(x²+3x+4)+9=?

答:
(x²+3x-2)(x²+3x+4)+9
=(x²+3x)²+2(x²+3x)-8+9
=(x²+3x)²+2(x²+3x)+1
=(x²+3x+1)²