因式分解:(x²+3x-2)(x²+3x+4)+9=?
问题描述:
因式分解:(x²+3x-2)(x²+3x+4)+9=?
答
答:
(x²+3x-2)(x²+3x+4)+9
=(x²+3x)²+2(x²+3x)-8+9
=(x²+3x)²+2(x²+3x)+1
=(x²+3x+1)²