log2为底(x+1)
问题描述：
log2为底(x+1)
答
log2[x+1]≤log4[3x+1]定义：x+1>0 x>-13x+1>0 x>-1/3log2[x+1]≤(1/2)log2[3x+1]2log2[x+1]≤log2[3x+1]log2[x+1]²≤log2[3x+1](x+1)²≤3x+1x²+2x+1≤3x+1x²-x≤0x(x-1)≤0得0≤x≤1...