等差数列{an}中a3-a2=6,a4=-22数列{an}的前n项和为Sn求数列{an}的通项公式,求数列中满足10

a3-a2=6,所以d=6,a4=a1+3d,所以a1=a4-3d= -40.an=a1+(n-1)d=6n-46.
10