化简代数式{(a-b)/(a+2b)}/{(a²-b²)/(a²+4ab+4b²)}-1
问题描述:
化简代数式{(a-b)/(a+2b)}/{(a²-b²)/(a²+4ab+4b²)}-1
答
{(a-b)/(a+2b)}/{(a²-b²)/(a²+4ab+4b²)}-1={(a-b)/(a+2b)}/{(a+b)(a-b)/(a+2b)²}-1=(a-b)(a+2b)²/(a+b)(a-b)(a+2b)²-1=(a+2b)/(a+b)-1=b/(a+b)...