2x²+xy-y²求分解过程,怎么等于(2x-y)(x+y)
问题描述:
2x²+xy-y²求分解过程,怎么等于(2x-y)(x+y)
答
2x²+xy-y²
=x²+xy+x²-y²
=(x²+xy)+(x²-y²)
=x(x+y)+(x+y)(x-y)
=(x+y)[x+(x-y)]
=(x+y)(2x-y)
即原式=(2x-y)(x+y)