当x∈M,求函数f(x)=log2(x/2)log2(x/4)的max&min= =m是啥
问题描述:
当x∈M,求函数f(x)=log2(x/2)log2(x/4)的max&min
= =m是啥
答
f(x)=log2(x/2)*log2(x/4)
=(log2 x -log2 2)(log2 x- log2 4)
=(log2 x- 1)(log2 x-2)
=(log2 x)^2-3log2 x +2
关于log2 x的一元二次函数
M没有解不了