化简：1/(x+1)-(x-3)/(x2-1)×(x2-2x+1)/(x2+4x+3)——题目没有出错,能者快来,
问题描述：
化简：1/(x+1)-(x-3)/(x2-1)×(x2-2x+1)/(x2+4x+3)——题目没有出错,能者快来,
答
原式
=1/(x+1)-[(x-3)(x-1)(x-1)]/[(x+1)(x-1)(x+1)(x+3)]
=1/(x+1)-[(x-3)(x-1)]/[(x+1)(x+1)(x+3)]
=1/(x+1)×{1-[(x-3)(x-1)]/[(x+1)(x+3)]}
=1/(x+1)×{8x/[(x+1)(x+3)]}
=8x/[(x+1)(x+1)(x+3)]