因式分解(m²+n²)²-4m²n² x ²+2x+1-y² (a+1)²(2a-3)-2(a+1)(3-2a)+2a-3 x²-2xy+y²-2x+2y+1

(m²+n²)²-4m²n² =(m^2-n^2)=(m+n) ²(m-n)²
x ²+2x+1-y²=(x+1) ²-y ²=(x+1-y)(x+1+y)
(a+1)²(2a-3)-2(a+1)(3-2a)+2a-3 =(2a-3)[(a+1)²+2(a+1)+1]=(2a-1)(a+2)²
x²-2xy+y²-2x+2y+1=(x-y)²-2(x-y)+1=(x-y-1)²
回答数学不容易，自己做的，满意请采纳哦

(m²+n²)²-4m²n²=(m²-n²)²
x ²+2x+1-y²=(x+1)²-y²=((x+y+1)(x-y+1)
(a+1)²(2a-3)-2(a+1)(3-2a)+2a-3=(2a-3)*(a+2)²
x²-2xy+y²-2x+2y+1=(x-y-1)²

1.（m+n)2(m-n)2 2.（x+1+y）（x+1-y) 3.(a+1)(a-1)(a-3) 4.(x-y-1)2

(m²-n²)²
（x-y+1)(x+y+1)
(a+2)²(2a-3)
(x-y-1)²

(m²+n²)²-4m²n² =m²n²(m²n²-4)=[(mn)²-2²]=m²n²(mn+2)(mn-2)x ²+2x+1-y² =(x+1)²-y²=（x+1+y)(x+1-y)(a+1)²(2a-3)-2(a...

(m²+n²)²-4m²n²
=（m²+n²+2mn）（m²+n²-2mn）
=（m+n）²（m-n）²

x ²+2x+1-y²
=（x+1）²-y²
=（x+y+1）（x-y+1）

(a+1)²(2a-3)-2(a+1)(3-2a)+2a-3
=(2a-3)〔(a+1)²+ 2(a+1)+1〕
=(2a-3) (a+2)²

x²-2xy+y²-2x+2y+1
=(x-y)²-2(x-y)+1
=(x-y-1)²

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