1.已知ab=6,bc=3,则a^3b^4c^2除以1/3a^2b^2c的值为______ 2.多项式2x^4-4x^2-1除以2x,余式为2x-1,则商式为______
问题描述：
1.已知ab=6,bc=3,则a^3b^4c^2除以1/3a^2b^2c的值为______ 2.多项式2x^4-4x^2-1除以2x,余式为2x-1,则商式为______
答
ab=6,bc=3， 两式相乘得 abc=18； a^3b^4c^2÷(1/3a^2b^2c)=3abc=3×18=54.
答
ab=6,bc=3,a^3b^4c^2除以1/3a^2b^2c=3ab^2c=3（ab）*（bc）=3*6*3=54 2x^4-4x^2-1除以2x,余式为2x-1,所以商式为[2x^4-4x^2-1-(2x-1)]/2x=x3-2x-1