解不等式:(1)x^2-2x-8<0 (2)x^2-4x+4≤0

问题描述:

解不等式:(1)x^2-2x-8<0 (2)x^2-4x+4≤0

x²-2x-8<0,解得:x∈(-2,4) ①;
X²-4X+4≤0,解得:X∈[2] ②;

(1)x^2-2x-8<0,
(x-4)(x+2)所以-2(2)x^2-4x+4≤0
(x-2)^2≤0,
所以x=2

(1)X^2-2X-8