求函数y=2sin(2x+3/π)(-π/6<π/6)的值域

问题描述:

求函数y=2sin(2x+3/π)(-π/6<π/6)的值域

3/π是π/3吧,
题目是:求y=2sin(2x+π/3)(-π/6<x<π/6)的值域
因为 -π/6≤x≤π/6 所以0 ≤2x+π/3≤2π/3
所以y=2sin(2x+π/3)(-π/6<x<π/6)的值域为[0,2]